A) \[C{{H}_{3}}COOH\]
B) \[ClC{{H}_{2}}COOH\]
C) \[C{{l}_{2}}CHCOOH\]
D) \[C{{l}_{3}}CCOOH\]
Correct Answer: C
Solution :
The groups, which have greater \[-I\]effect increases the acidic strength by decreasing negative charge on the carboxylate ion. As the acidic strength increases, reactivity of the groups decreases So, correct order is \[C{{l}_{3}}CCOOH<C{{l}_{2}}CHCOOH<ClC{{H}_{2}}COOH<\] \[C{{H}_{3}}COOH\]
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