J & K CET Engineering J and K - CET Engineering Solved Paper-2007

  • question_answer
    The wavelength of a spectral line in Lyman series, when electron jumps back from 2nd orbit, is

    A) \[\text{1162 }\overset{\text{o}}{\mathop{\text{A}}}\,\]      

    B) \[1216\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C)  \[1362\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D) \[1176\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: B

    Solution :

     \[\frac{1}{\lambda }={{R}_{H}}\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\] For Lyman series \[{{n}_{1}}=1,{{n}_{2}}=2\] \[\frac{1}{\lambda }=10,9678\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(2)}^{2}}} \right]\] \[=\frac{10,9678\times 3}{4}\] \[\lambda =1216\,\overset{\text{o}}{\mathop{\text{A}}}\,\]


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