A) \[1\]
B) \[2\]
C) \[3\]
D) \[4\]
Correct Answer: B
Solution :
Given, that, \[\left| \begin{matrix} 1 & 1 & 0 \\ 2 & 0 & 3 \\ 5 & -6 & x \\ \end{matrix} \right|=29\] \[\Rightarrow \] \[1(0+18)-1(2x-15)=29\] \[\Rightarrow \] \[18-2x+15=29\] \[\Rightarrow \] \[2x=4\] \[\Rightarrow \] \[x=2\]You need to login to perform this action.
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