A) \[A\]
B) \[-A\]
C) \[adj\,(A)\]
D) \[-adj\,(A)\]
Correct Answer: C
Solution :
\[A=\left[ \begin{matrix} \cos \,\alpha & -\sin \alpha & 0 \\ \sin \,\alpha & \cos \,\alpha & 0 \\ 0 & 0 & 1 \\ \end{matrix} \right]\] \[\therefore \] \[|A|=1.({{\cos }^{2}}\,\alpha +{{\sin }^{2}}\alpha )=1\] Now, \[{{A}^{-1}}=\frac{1}{|A|}\,adj\,(A)=adj\,(A)\]You need to login to perform this action.
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