A) \[\frac{1}{3}\]
B) \[1\]
C) \[\frac{1}{5}\]
D) \[\frac{1}{6}\]
Correct Answer: D
Solution :
Given, \[P(A\cup B)=\frac{1}{2}\] and \[P(\bar{A})=\frac{2}{3}\] \[\therefore \] \[P(A)=1-\frac{2}{3}=\frac{1}{3}\] Now.\[P(\bar{A}\cap B)=P(A\cup B)-P(A)=\frac{1}{2}-\frac{1}{3}=\frac{1}{6}\]You need to login to perform this action.
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