A) \[\frac{2}{3}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{4}\]
D) \[\frac{3}{4}\]
Correct Answer: B
Solution :
Given, \[P(A)=\frac{1}{2}P(B)\] \[\Rightarrow \] \[P(B)=2P(A)\] and \[A\cup B=S\] \[\therefore \] \[P(A\cup B)=P(S)=1\] \[\Rightarrow \] \[P(A)+P(B)=1\]\[[\because \,\,P(A\cap B)=0]\] \[\Rightarrow \] \[P(A)+2P(A)=1\] \[\Rightarrow \] \[P(A)=\frac{1}{3}\]You need to login to perform this action.
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