J & K CET Engineering J and K - CET Engineering Solved Paper-2007

  • question_answer
    A wire P has a resistance of \[20\,\Omega \]. Another wire Q of same material but length twice that of P has resistance of \[8\,\,\,\Omega \]. If r is the radius of cross-section of P, the radius of cross-section of Q is

    A)  \[r\]

    B)  \[\frac{r}{\sqrt{2}}\]

    C)  \[\sqrt{5}\,r\]

    D)  \[2\,r\]

    Correct Answer: C

    Solution :

    Resistance, \[R=\frac{\rho l}{A}\] For wire P, \[20=\frac{\rho l}{\pi {{r}^{2}}}\] ??(i) Similarly, for wire Q,  \[8=\frac{\rho \,(2l)}{\pi {{(r')}^{2}}}\] ?..(ii)                     Dividing Eq. (i) by Eq. (ii), we have \[\frac{20}{8}=\frac{\rho l}{\pi {{r}^{2}}}\times \frac{\pi {{(r')}^{2}}}{\rho \,(2l)}\] \[\Rightarrow \] \[5={{\left( \frac{r'}{r} \right)}^{2}}\] \[\Rightarrow \] \[r'=\sqrt{5}r\]


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