A) \[2\]
B) \[2\sqrt{2}\]
C) \[2\sqrt{3}\]
D) \[3\sqrt{2}\]
Correct Answer: B
Solution :
Rotational kinetic energy \[=\frac{1}{2}I\,\,{{\omega }^{2}}\] \[\therefore \] Rotational \[KE=\frac{1}{2}\left[ \frac{1}{2}m{{r}^{2}} \right]\frac{{{v}^{2}}}{{{r}^{2}}}\] \[\left( where\,\,\,\,I=\frac{1}{2}\,m{{r}^{2}} \right)\] \[4=\frac{1}{2}\left[ \frac{1}{2}(2){{r}^{2}} \right]\frac{{{v}^{2}}}{{{r}^{2}}}\] \[\Rightarrow \] \[{{v}^{2}}=8\] \[v=2\sqrt{2}m/s\]You need to login to perform this action.
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