A) \[2\,C\]
B) \[C/2\]
C) \[(1+K)C/2\]
D) \[2C(1+K)\]
Correct Answer: C
Solution :
The dielectric is introduced such that, half of its area is occupied by it. In the given case the two capacitors are in parallel. \[\therefore \] \[C'={{C}_{1}}+{{C}_{2}}\] \[{{C}_{1}}=\frac{A\,\,{{\varepsilon }_{0}}}{2d}\] and \[{{C}_{2}}=\frac{KA{{\varepsilon }_{0}}}{2d}\] Thus, \[C'=\frac{A{{\varepsilon }_{0}}}{2d}+\frac{KA\,\,{{\varepsilon }_{0}}}{2d}\] \[C'=\frac{C}{2}(1+K)\]You need to login to perform this action.
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