A) \[r\]
B) \[\frac{r}{\sqrt{2}}\]
C) \[\sqrt{5}\,r\]
D) \[2\,r\]
Correct Answer: C
Solution :
Resistance, \[R=\frac{\rho l}{A}\] For wire P, \[20=\frac{\rho l}{\pi {{r}^{2}}}\] ??(i) Similarly, for wire Q, \[8=\frac{\rho \,(2l)}{\pi {{(r')}^{2}}}\] ?..(ii) Dividing Eq. (i) by Eq. (ii), we have \[\frac{20}{8}=\frac{\rho l}{\pi {{r}^{2}}}\times \frac{\pi {{(r')}^{2}}}{\rho \,(2l)}\] \[\Rightarrow \] \[5={{\left( \frac{r'}{r} \right)}^{2}}\] \[\Rightarrow \] \[r'=\sqrt{5}r\]You need to login to perform this action.
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