A) \[T\]
B) \[\frac{T}{2}\]
C) \[\frac{T}{4}\]
D) \[2T\]
Correct Answer: A
Solution :
Time period \[T=2\pi \sqrt{\frac{I}{MB}}\] As the magnet is cut into two equal parts along axis, then for each part \[I'=\frac{I}{2}\] \[M'=\frac{M}{2}\] \[\therefore \] Time period of new magnet, \[T'=\sqrt{\frac{I'}{M'B}}=\sqrt{\frac{I\times 2}{2\times M\times B}}\] \[T'=T\]You need to login to perform this action.
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