2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    \[\underset{x\to 1}{\mathop{\lim }}\,\frac{{{x}^{m}}-1}{{{x}^{n}}-1}\]is equal to

    A)  \[\frac{n}{m}\]

    B)  \[\frac{m}{n}\]

    C)  \[\frac{2m}{n}\]

    D)  \[\frac{2n}{m}\]

    Correct Answer: B

    Solution :

    \[\underset{x\to 1}{\mathop{\lim }}\,\frac{{{x}^{m}}-1}{{{x}^{n}}-1}\] \[=\underset{x\to 1}{\mathop{\lim }}\,\,\,\frac{m{{x}^{m}}^{-1}}{n{{x}^{n}}^{-1}}\] (using L? Hospital?s rule) \[=\frac{m}{n}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner