A) \[1/2\text{ }sq\text{ }unit\]
B) \[1/4\text{ }sq\text{ }unit\]
C) \[1/8\text{ }sq\text{ }unit\]
D) \[1/16\text{ }sq\text{ }unit\]
Correct Answer: A
Solution :
\[\therefore \] Required area \[=2\int_{0}^{1}{(x-{{x}^{3}})dx}\] \[=2\left[ \frac{{{x}^{2}}}{2}-\frac{{{x}^{4}}}{4} \right]_{0}^{1}\] \[=2\left[ \frac{1}{2}-\frac{1}{4} \right]=2\times \frac{1}{4}\] \[=\frac{1}{2}sq\,\,unit\]You need to login to perform this action.
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