A) 1500
B) 10,000
C) \[\text{2}\text{.4}\times \text{1}{{\text{0}}^{5}}\]
D) \[\text{2}\times \text{1}{{\text{0}}^{12}}\]
Correct Answer: C
Solution :
Given, weight of \[PVC,\,w=4\,g\] Volume of solution, \[V=1\,L\] Osmotic pressure, \[\pi =4.2\times {{10}^{-4}}\] Temperature, \[T=27{{\,}^{o}}C=27+273=300\,K\] \[\Rightarrow \] \[\pi V=nRT\] or \[\pi \,V=\frac{w}{M}RT\](\[M=\]molecular weight) \[4.1\times {{10}^{-4}}\times 1=\frac{4}{M}\times 0.0821\times 300\] \[M=\frac{4\times 0.0821\times 300}{4\times {{10}^{-4}}\times 1}\] \[\therefore \] \[M=2.4\times {{10}^{5}}\]You need to login to perform this action.
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