A) 2
B) 0
C) 2.5
D) 3.5
Correct Answer: C
Solution :
Let the oxidation state of sulphur in\[\text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{4}}}{{\text{O}}_{\text{6}}}\] is\[x.\] \[N{{a}_{2}}{{S}_{4}}{{O}_{6}}\] \[1\times 2+4\times x+(-2)\times 6=0\] \[2+4x-12=0\] \[4x-10=0\] \[4x=10\] \[x=\frac{10}{4}=2.5\]You need to login to perform this action.
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