A) a symmetric matrix
B) a skew symmetric matrix
C) a unit matrix
D) an elementary matrix
Correct Answer: B
Solution :
Now, \[{{\left[ \frac{1}{2}\,(A-A') \right]}^{'}}=\frac{1}{2}(A-A')'\] \[=\frac{1}{2}(A'-A)\] \[=-\frac{1}{2}(A-A')\] Hence, it is a skew symmetric matrix.You need to login to perform this action.
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