A) \[v\]
B) \[2v\]
C) \[4v\]
D) \[9v\]
Correct Answer: C
Solution :
Terminal velocity \[v\propto {{r}^{2}}\] \[\therefore \] \[\frac{v'}{v}=\frac{{{(2R)}^{2}}}{{{(R)}^{2}}}\] or \[v'=4v\]You need to login to perform this action.
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