A) \[2\]
B) \[5.5\]
C) \[4\]
D) \[1.5\]
Correct Answer: C
Solution :
Potential energy of the system \[\frac{-kqQ}{x}-\frac{kQq}{x}+\frac{k{{q}^{2}}}{2x}=0\] \[\Rightarrow \] \[\frac{-4kqQ+k{{q}^{2}}}{2x}=0\] \[\Rightarrow \] \[k{{q}^{2}}=4kQq\] \[\frac{q}{Q}=4\]You need to login to perform this action.
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