A) \[3\text{ }mm\]
B) \[1\text{ }mm\]
C) \[\text{2 }mm\]
D) \[\text{4 }mm\]
Correct Answer: C
Solution :
Fringe width, \[\beta =\frac{\lambda D}{d}\] \[\frac{\beta }{\lambda }=\frac{D}{d}\]= constant for an experiment \[\therefore \] \[\frac{\beta }{\lambda }=\frac{\beta '}{\lambda '}\] \[\Rightarrow \] \[\frac{3}{6000}=\frac{\beta '}{4000}\] \[\Rightarrow \] \[\beta '=2mm\]You need to login to perform this action.
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