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J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    The   domain   of  the   real   function  \[f(x)=\frac{1}{\sqrt{4-{{x}^{2}}}}\]is

    A)  the set of all real numbers

    B)  the set of all positive real numbers

    C)  \[(-2,\,2)\]

    D)  \[[-2,\,2]\]

    Correct Answer: C

    Solution :

    Given, \[f(x)=\frac{1}{\sqrt{4-{{x}^{2}}}}\] For domain of \[f(x),\sqrt{4-{{x}^{2}}}>0\] \[\Rightarrow \] \[4-{{x}^{2}}>0\] \[\Rightarrow \] \[{{x}^{2}}<4\] \[\Rightarrow \] \[x\le \pm 2\] \[\therefore \] Domain \[=(-2,2)\]


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