A) 0.6
B) 0.5
C) 0.8
D) 0,4
Correct Answer: D
Solution :
Let the moles of \[A=x\] \[\therefore \]The moles of \[B=x\][\[\because \]mixture is equimolar.] Mole fraction of \[A=\frac{x}{x+x}=0.5=\text{mole}\] fraction of B. Thus, \[{{p}_{T}}=p_{A}^{o}{{X}_{A}}+p_{B}^{o}{{X}_{B}}\] \[{{p}_{T}}=150\times 0.5+100\times 0.5\] \[=125\] \[\therefore \]Mole fraction of B in vapour mixture \[=\frac{p_{B}^{o}{{X}_{B}}}{{{p}_{T}}}\] \[=\frac{100\times 0.5}{125}\]You need to login to perform this action.
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