A) +8 and +7
B) +3 and +3
C) +6 and +6
D) +4 and +6
Correct Answer: B
Solution :
Both peroxomonosulphuric acid \[({{H}_{2}}S{{O}_{5}})\] and peroxod.isulphuric acid\[({{H}_{2}}{{S}_{2}}{{O}_{8}})\]have peroxide linkage and have the following structures. \[H-O-\underset{O}{\overset{O}{\mathop{\underset{||}{\overset{||}{\mathop{S}}}\,}}}\,-\underbrace{O-O}_{\begin{smallmatrix} \text{peroxide} \\ \text{linkaage} \end{smallmatrix}}-H\] Thus, oxidation number of S in \[{{H}_{2}}S{{O}_{5}},\]is calculated as \[\underset{(for\,H)}{\mathop{2\times (+\,1)}}\,\,+\,\,\underset{(for\,S)}{\mathop{x}}\,+\,\underset{(for\,\text{O)}}{\mathop{3\times (-2)}}\,\,+\underset{\text{for}\,\text{peroxide}}{\mathop{2\times (-1)}}\,\] \[2+x-6-2=0\] \[x=+\,\,6\] \[H-O-\underset{O}{\overset{O}{\mathop{\underset{||}{\overset{||}{\mathop{S}}}\,}}}\,-\underbrace{O-O}_{\begin{smallmatrix} \text{peroxide} \\ \text{linkage} \end{smallmatrix}}-\underset{O}{\overset{O}{\mathop{\underset{||}{\overset{||}{\mathop{S}}}\,}}}\,-O-H\] Thus, oxidation number of S in\[{{\text{H}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{8}}}\] is calculated as \[\underset{(for\,H)}{\mathop{2\times (+\,1)}}\,\,+\,2\times \,\underset{(for\,S)}{\mathop{(x)}}\,+\,\underset{(for\,\text{O)}}{\mathop{6\times (-2)}}\,\,+\underset{\text{for}\,\text{peroxide}}{\mathop{2\times (-1)=0}}\,\] \[2+2x-12+2=0\] \[\therefore \] \[x=+\,6\]You need to login to perform this action.
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