question_answer

The fundamental frequencies of an open and a closed tube, each of same length L with v as the speed of sound in air, respectively are

A)  \[\frac{v}{2L}\] and \[\frac{v}{L}\]

B)  \[\frac{v}{L}\] and \[\frac{v}{2L}\]

C)  \[\frac{v}{2L}\] and \[\frac{v}{4L}\]

D)  \[\frac{v}{4L}\] and \[\frac{v}{2L}\]

Correct Answer: C

Solution :

Fundamental mode	Fundamental mode
\[{{v}_{1}}=\frac{v}{4\,l}\]	\[{{v}_{1}}=\frac{v}{{{\lambda }_{1}}}=\frac{v}{2l}\]