A) \[\frac{6}{37}\]
B) \[\frac{-6}{31}\]
C) \[\frac{-6}{37}\]
D) \[\frac{-6}{35}\]
Correct Answer: D
Solution :
Given, straight lines \[2x+5ay-1=0\] and \[3x+7y+7=0\] are mutually perpendicular. Therefore, \[{{m}_{1}}{{m}_{2}}=-1\] \[\frac{-2}{5a}\times \frac{-3}{7}=-1\] \[\Rightarrow \] \[a=\frac{-6}{35}\]You need to login to perform this action.
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