A) \[{{x}^{2}}+{{y}^{2}}-2x+6y-22=0\]
B) \[{{x}^{2}}+{{y}^{2}}+2x+6y-11=0\]
C) \[{{x}^{2}}+{{y}^{2}}-2x+6y+22=0\]
D) \[{{x}^{2}}+{{y}^{2}}-2x-6y-22=0\]
Correct Answer: D
Solution :
Since, \[\angle APB=\frac{\pi }{2}\] Therefore, A and B are the extreme points of the diameter of the circle.You need to login to perform this action.
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