A) \[17\,A\]
B) \[7\,A\]
C) zero
D) \[\frac{10}{7}A\]
Correct Answer: B
Solution :
In steady state, the branch containing capacitor will become ineffective (ie, we can ignore \[1\,\Omega \]resistance) The equivalent circuit will now be \[\therefore \] \[{{R}_{eq}}=\frac{{{R}_{1}}\times {{R}_{2}}}{{{R}_{1}}+{{R}_{2}}}=\frac{5\times 2}{5+2}=\frac{10}{7}\] Now, \[V=iR\] \[10=\frac{i\times 10}{7}\] \[\Rightarrow \] \[i=7A\]You need to login to perform this action.
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