\[x=x\] | \[-1\] | \[0\] | \[1\] | \[2\] |
\[P(X=X)\] | \[0.2\] | \[0.1\] | \[0.4\] | \[\lambda \] |
A) \[0.8\]
B) \[0.6\]
C) \[0.5\]
D) \[0.7\]
Correct Answer: D
Solution :
We know that, total probability \[=1\] \[\Rightarrow \] \[P(-1)+P(1)+P(2)=1\] \[\Rightarrow \] \[0.2+0.1+0.4+\lambda =1\] \[\Rightarrow \] \[\lambda =1-0.7=0.3\] Then \[P(0<x\le 2)=P(1)+P(2)\] \[=0.4+0.3\] \[=0.7\]You need to login to perform this action.
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