J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    The energy that is associated with one gram of mass is

    A)  \[9\times {{10}^{-13}}\,J\]     

    B)  \[9\times {{10}^{-16}}\,J\]

    C)  \[9\times {{10}^{13}}\,J\]      

    D)  \[9\times {{10}^{16}}\,J\]

    Correct Answer: C

    Solution :

    If \[m=1amu,\,\,\,c=3\times {{10}^{8}}m/s\]then \[E=931\,MeV\] \[1\,amu=1.6\times {{10}^{-27}}kg\] \[1.6\times {{10}^{-27}}kg\] is equal  to \[931\text{ }MpV\] \[\therefore \] 1 kg is equal to \[\frac{931}{1.6\times {{10}^{-27}}}MeV\] \[\therefore \] 1 g is equal to \[\frac{931\times {{10}^{-3}}}{1.6\times {{10}^{-27}}}MeV\] \[=5.81\times {{10}^{26}}MeV\] \[5.81\times {{10}^{26}}MeV=5.81\times {{10}^{26}}\times 1.6\times {{10}^{-13}}J\] \[=9.2\times {{10}^{13}}J\]


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