A) \[37.5\text{ }W\]
B) \[75\text{ }W\]
C) \[80\text{ }W\]
D) \[40\text{ }W\]
Correct Answer: A
Solution :
When connected in series power dissipated \[{{P}_{S}}=\frac{{{P}_{1}}{{P}_{2}}}{{{P}_{1}}+{{P}_{2}}}\] \[=\frac{100\times 60}{100+60}=\frac{6000}{160}=37.5W\]
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