A) \[\frac{e}{m}\tau \]
B) \[\frac{m}{e}\tau \]
C) \[\frac{e}{m\tau }\]
D) \[\frac{m}{e\tau }\]
Correct Answer: A
Solution :
Drift velocity per unit electric field is called mobility of electron, ie, \[\mu =\frac{{{v}_{d}}}{E}=\frac{E}{\rho neE}\] Now, \[\rho =\frac{m}{n{{e}^{2}}\tau }\] \[\therefore \] s\[\mu =\frac{n{{e}^{2}}\tau }{mne}=\frac{e\tau }{m}\]
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