A) \[{{60}^{o}}\]
B) \[{{30}^{o}}\]
C) \[{{25}^{o}}\]
D) \[{{54.74}^{o}}\]
Correct Answer: B
Solution :
Refractive index, \[\mu =\tan \theta =\sqrt{2}\] Now according to Snell?s law \[\sqrt{2}=\frac{\sin \,(54.74)}{\sin r}\] \[\sin \,r=\frac{0.816}{\sqrt{2}}\] \[\sin \,r=0.57\] \[r={{35}^{o}}\simeq {{30}^{o}}\]You need to login to perform this action.
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