A) \[2i\]
B) \[3\,\sqrt{2}\]
C) \[-3\,\sqrt{2}\]
D) \[5\,\sqrt{2}\]
Correct Answer: B
Solution :
Given, quadratic equation is \[{{x}^{2}}-(3\sqrt{2}-2i)x-6\sqrt{2}i=0\] Its one root is \[-2i\] Let it?s another root is \[\alpha \] Then, sum of the roots \[\alpha -2i=3\sqrt{2}-2i\] \[\therefore \] \[\alpha =3\sqrt{2}\]You need to login to perform this action.
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