A) (i) < (ii) < (iii) < (iv)
B) (iv) < (iii) < (ii) < (i)
C) (iv) < (ii) < (iii) < (i)
D) (iv) < (i) < (ii) < (iii)
Correct Answer: C
Solution :
According to \[(n+l)\] rule, the lower the value of \[(n+l)\] for an orbital, the lower is its energy. If two orbitals have the same value of\[(n+l),\] the orbital with lower value of n will have the lower energy. Hence, the order of increasing energy of electron is as\[\text{IV}\] | \[<\] | \[\text{II}\] | \[<\] | \[\text{III}\] | < | \[\text{I}\] |
\[n=3\] | \[n=4\] | \[n=3\] | \[n=4\] | |||
\[l=1\] | \[l=0\] | \[l=2\] | \[l=1\] | |||
\[n+l=4\] | \[n+l=4\] | \[n+l=5\] | \[n+l=5\] |
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