A) \[\pi \]
B) \[\frac{\pi }{2}\]
C) \[\frac{\pi }{4}\]
D) \[\frac{\pi }{8}\]
Correct Answer: C
Solution :
\[f(x)=|\sin \,2x|+|\cos \,2x|\] Since, \[|\sin x|+|\cos x|\] is a periodic function with period \[\pi /2.\] \[\therefore \] \[|\sin \,2x|+\cos \,2x|\] has period \[=\frac{1}{2}.\frac{\pi }{2}=\frac{\pi }{4}\]You need to login to perform this action.
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