A) \[B\,\,\sin \,\,\omega t\]
B) \[\frac{B{{R}^{2}}\omega }{2}\]
C) \[2\,B{{R}^{2}}\omega \]
D) \[B{{R}^{2}}\omega \]
Correct Answer: B
Solution :
The emf induced between the centre and the metallic ring is \[\frac{1}{2}B{{R}^{2}}\omega \].You need to login to perform this action.
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