A) \[{{227}^{o}}C\]
B) \[{{27}^{o}}C\]
C) \[{{327}^{o}}C\]
D) \[{{127}^{o}}C\]
Correct Answer: D
Solution :
\[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\frac{25}{100}=1-\frac{300}{{{T}_{1}}}\] \[\frac{300}{{{T}_{1}}}=1-\frac{25}{100}\] \[\frac{300}{{{T}_{1}}}=\frac{100-25}{100}\] \[\frac{300}{{{T}_{1}}}=\frac{75}{100}\] \[{{T}_{1}}=\frac{300\times 100}{75}\] \[{{T}_{1}}=400\] \[\therefore \] \[{{T}_{1}}=400-273\] \[={{127}^{o}}C\]You need to login to perform this action.
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