A) \[[-4,\,\,4]\]
B) \[(-\,\infty ,\,\,3]\]
C) \[(-\,\infty ,\,\,3)\]
D) \[[-4,\,\,\,3)\]
Correct Answer: C
Solution :
Given, \[f(x)=3-x,\,\,-4\le x\le 4\] Now, \[{{\log }_{e}}\,f\{(x)\}=lo{{g}_{e}}\,(3-x)\] Here, existance for the above function \[3-x>0\] \[\Rightarrow \] \[x-3<0\] \[\Rightarrow \] \[x<3\] So, the domain of \[{{\log }_{e}}\,\{f\,(x)\,\}\] is \[(-\infty ,\,3).\]You need to login to perform this action.
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