A) \[1.0\]
B) \[1.1\]
C) \[0.7\]
D) \[1.3\]
Correct Answer: D
Solution :
Given, \[P(A\cup B)=0.5\] and \[P(A\cap B)=0.2\] \[\therefore \] \[P({{A}^{c}})+P({{B}^{c}})=1-P(A)+1-P(B)\] \[=2-\{P\,(A)+P(B)\}\] ?..(i) \[\because \] \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\] \[\therefore \] \[0.5=P(A)+P(B)-0.2\] \[\Rightarrow \] \[P(A)+P(B)=0.7\] \[\therefore \] From Eq. (i), \[P({{A}^{c}})+P({{B}^{c}})=2-0.7\] \[=1.3\]You need to login to perform this action.
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