A) \[2\]
B) \[6\]
C) \[8\]
D) \[7\]
Correct Answer: A
Solution :
\[\therefore \] Length of perpendicular from the point \[(1,\,\,0,\,\,1)\] to the plane \[3x+\sqrt{6}y+7z+6=0\]is \[\frac{3(1)+\sqrt{6}(0)+7(1)+6}{\sqrt{{{3}^{2}}+{{(\sqrt{6})}^{2}}+{{(7)}^{2}}}}\] \[=\frac{16}{\sqrt{9+6+49}}=\frac{16}{\sqrt{64}}=\frac{16}{8}=2\]You need to login to perform this action.
You will be redirected in
3 sec