A) \[0\]
B) \[1\]
C) \[2\]
D) \[-2\]
Correct Answer: C
Solution :
Let \[I=\int_{-\pi /2}^{\pi /2}{\sqrt{1-{{\cos }^{2}}\theta }\,d\theta }\] \[=\int_{-\pi /2}^{\pi /2}{|\sin \theta |\,\,d\theta }\] \[=2\int_{0}^{\pi /2}{\sin \theta \,\,\,d\theta }\] \[=2[-\cos \,\theta ]_{0}^{\pi /2}\] \[=2\left( -\cos \frac{\pi }{2}+\cos \,{{0}^{o}} \right)\] \[=2(1)=2\]You need to login to perform this action.
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