A) \[b-a=ab\]
B) \[b+a=ab\]
C) \[a-b=ab\]
D) \[a+b=-ab\]
Correct Answer: A
Solution :
Since, points \[(a,\,0),\,\,(0,b)\] and \[(1,-1)\] are collinear. \[\therefore \] \[\left| \begin{matrix} a & 0 & 1 \\ 0 & b & 1 \\ 1 & -1 & 1 \\ \end{matrix} \right|=0\] \[\Rightarrow \] \[a(b+1)+0+1(0-b)=0\] \[\Rightarrow \] \[ab+a-b=0\] \[\Rightarrow \] \[b-a=ab\]You need to login to perform this action.
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