A) \[\frac{1}{5}\]
B) \[\frac{2}{5}\]
C) \[\frac{3}{5}\]
D) \[\frac{4}{5}\]
Correct Answer: A
Solution :
Given, \[3\tan \theta +4=0\] \[\Rightarrow \] \[\tan \theta =-\frac{4}{3}\] Since, \[\theta \] lies in IInd quadrant. \[\therefore \] \[\sin \theta =\frac{4}{5}\] and \[\cos \theta =\frac{-3}{5}\] \[\therefore \] \[\sin \theta +\cos \theta =\frac{4}{5}-\frac{3}{5}=\frac{1}{5}\]You need to login to perform this action.
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