A) 6
B) 4
C) 0
D) 3
Correct Answer: D
Solution :
Let oxidation number of Co be x; Oxidation number of\[{{H}_{2}}O=0;\] Oxidation number of\[~CN=-1\] Therefore \[{{[Co(CN)({{H}_{2}}O){{(en)}^{2}}]}^{2}}\] \[\therefore \] \[x+2(0)-1=+\,2\] \[x-1=+\,2=+\,3\]or 3 Hence, coordination number of Co is 3.You need to login to perform this action.
You will be redirected in
3 sec