A) \[1\]
B) \[0\]
C) Not defined
D) \[-1\]
Correct Answer: A
Solution :
\[\underset{x\to 1}{\mathop{\lim }}\,\frac{x-1}{{{\log }_{e}}x};\,\,\left( from\frac{0}{0} \right)\] [Use L? Hospital rule] \[=\underset{x\to 1}{\mathop{\lim }}\,\frac{1}{1/x}=\underset{x\to 1}{\mathop{\lim }}\,x=1\]You need to login to perform this action.
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