A) \[2.71\,V\]
B) \[2.03\,V\]
C) \[-2.71\,V\]
D) \[-2.03\,V\]
Correct Answer: A
Solution :
Given,\[E_{{{A}^{2+}}/A}^{o}=0.34\,V,E_{{{x}^{2+}}/x}^{o}=-2.37V\] Cell voltage\[=E_{cathode}^{o}-E_{Anode}^{o}\] \[=0.34-(-2.37)=2.71\,V\]You need to login to perform this action.
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