A) \[[1,\,\,2]\]
B) Null set
C) \[x\ge 1\]
D) Set of real numbers
Correct Answer: B
Solution :
Given, linear in equations are \[x-2y\ge 0;\,\,\,\,\,\,\,2x-y\le -2;\] \[x\ge 0,\,\,\,\,y\ge 0\] Since, the intersection point of both lines intersect in third quadrant, i.e., x and y coordinate are both negative but given that x and y are both positive. So, solution of given inequalities is ??Null set??.You need to login to perform this action.
You will be redirected in
3 sec