J & K CET Engineering J and K - CET Engineering Solved Paper-2013

  • question_answer
    Suppose \[{{A}_{1}},{{A}_{2}}.....,{{A}_{30}}\]are thirty sets each  with five elements and \[{{B}_{1}},{{B}_{2}}.....,{{B}_{n}}\] are 'n' sets each with three elements. Let     \[\underset{i=1}{\mathop{\overset{30}{\mathop{\cup }}\,}}\,\,\,{{A}_{i}}=\underset{j=1}{\mathop{\overset{n}{\mathop{\cup }}\,}}\,\,\,\,{{B}_{j}}=S.\] Assume that each element of S belongs to exactly 10 of \[{{A}_{i}}s\] and exactly 9 of \[{{B}_{j}}s,\]then the value of x is

    A)  \[90\]                  

    B)  \[15\]

    C)  \[9\]                 

    D)  45

    Correct Answer: D

    Solution :

    If elements are not repeated then number of elements in \[{{A}_{1}}\cup {{A}_{2}}\cup {{A}_{3}}\cup ......\cup {{A}_{30}}\] is \[30\times 5.\] but each element is used 10 time. \[\therefore \] \[S=\frac{30\times 5}{10}=15\] ?..(i) Similarly, if elements in \[{{B}_{1}},\,{{B}_{2}}.....{{B}_{n}}\] are not repeated, then total number of elements is 3n but each elements is repeated 9 times. \[S=\frac{3n}{9}\] \[\Rightarrow \] \[15=\frac{3n}{9};\] [from Eq. (i)] \[\therefore \] \[n=45\]


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