A) highly acidic
B) neutral
C) highly basic
D) slightly acidic
Correct Answer: B
Solution :
We know that \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] So, \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}},{{H}_{2}}S{{O}_{4}}\,NaOH\] \[1\times 100\] \[{{N}_{2}}\times 100\] \[{{N}_{2}}=1\] \[\because \]100 mL of \[\text{1 N }{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]will neutralize 100 mL of \[\text{1N NaOH}\]so, the solution will be neutral.You need to login to perform this action.
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