A) 3
B) 2.5
C) 2
D) 1.5
Correct Answer: B
Solution :
We know that N3 molecule is having 14 electrons so. \[{{\text{N}}_{\text{2}}}\text{=14}\] \[N_{2}^{+}=14-1=13,\]according to MOT (Molecular orbital theory) the configruation will be \[N_{2}^{+}=KK\,\sigma 2{{S}^{2}}\,{{\sigma }^{*}}2{{S}^{2}}\,\pi 2p_{x}^{2}\,\pi 2p_{y}^{2}\,\sigma 2p_{z}^{1}\] Bond order \[=\frac{1}{2}\] [Bonding - Antibonding] \[=\frac{1}{2}[7-2]\] \[=2\frac{1}{2}=2.5\]
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