A) \[9:16\]
B) \[16:9\]
C) \[3:4\]
D) \[4:3\]
Correct Answer: B
Solution :
Power \[=\frac{{{V}^{2}}}{R}\] As V is same for both bulbs,, so, Power \[\propto \frac{1}{R}\] so Intensity \[\propto \frac{1}{R}\] \[\Rightarrow \] So, \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{16}{9}\]You need to login to perform this action.
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